Re: UPA violation or not?

I'm a little confused about this question.  Not only does it look like a 
UPA violation, it looks a little bit like the simple examples of UPA 
violations that are used to introduce the topic.  In DTD terms, this is 
like (pongo?, pongo?),  except that since we have counting it's (pongo[0-2], pongo[0-2]). 

A single pongo matches either the first or the second particle.  The 
attribution to particles is thus ambiguous for at least one instance. QED.

Is there a subtlety in the example that I am missing?  It's true that the 
two particles have the same value for {term}, but that doesn't make them 
the same particle.  Apologies if I'm missing something obvious.

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Noah Mendelsohn 
IBM Corporation
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1-617-693-4036
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